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Eclipse常用快捷键

发表于 2016-07-19   |   分类于 工具   |  
转载在网上搜eclipse快捷键,可以搜出一大堆,大多罗列了n多 ...
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Java中Object转String

发表于 2016-07-18   |   分类于 java基础   |  
在java项目的实际开发和应用中,常常需要用到将对象转为Stri ...
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Add Binary

发表于 2016-07-17   |   分类于 leetcode   |  
Add BinaryGiven two binary strings, return their sum (also a binary string). For example,a = “11”b = “1”Return “100”. java思路:先 ...
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String to Integer (atoi)

发表于 2016-07-17   |   分类于 leetcode   |  
String to Integer (atoi)Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are ...
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Valid Palindrome

发表于 2016-07-17   |   分类于 leetcode   |  
Valid PalindromeGiven a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example,“A man, a plan, a canal: Panama” is a palindrome ...
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evaluate-reverse-polish-notation

发表于 2016-07-17   |   分类于 leetcode   |  
evaluate-reverse-polish-notationEvaluate the value of an arithmetic expression in Reverse Polish Notation.Valid operators are+,-,*,/. Each operand may be an integer or another expression.Some examples ...
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Copy list with random pointer

发表于 2016-07-16   |   分类于 leetcode   |  
138. Copy List with Random PointerA linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.&#x ...
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gas station

发表于 2016-07-15   |   分类于 leetcode   |  
There are N gas stations along a circular route, where the amount of gas at station i isgas[i].You have a car with an unlimited gas tank and it costscost[i]of gas to travel from station i to its next ...
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candy

发表于 2016-07-15   |   分类于 leetcode   |  
135. CandyThere are N children standing in a line. Each child is assigned a rating value. You are giving candies to these children subjected to the following requirements: Each child must have at leas ...
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leetcode中等题

发表于 2016-07-13   |   分类于 leetcode   |  
338. Counting BitsGiven a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them ...
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1234…7
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